python中将阿拉伯数字转换成中文的实现代码

代码如下:

#!/usr/bin/python #-*- encoding: utf-8 -*- import types class notintegererror(exception): pass class outofrangeerror(exception): pass _mapping = (u’零’, u’一’, u’二’, u’三’, u’四’, u’五’, u’六’, u’七’, u’八’, u’九’, ) _p0 = (u”, u’十’, u’百’, u’千’, ) _s4, _s8, _s16 = 10 ** 4 , 10 ** 8, 10 ** 16 _min, _max = 0, 9999999999999999 def _to_chinese4(num): ””’转换[0, 10000)之间的阿拉伯数字 ”’ assert(0 = 10: lst.append(num % 10) num = num / 10 lst.append(num) c = len(lst) # 位数 result = u” for idx, val in enumerate(lst): if val != 0: result += _p0[idx] + _mapping[val] if idx < c - 1 and lst[idx + 1] == 0: result += u'零' return result[::-1].replace(u'一十', u'十') def _to_chinese8(num): assert(num < _s8) to4 = _to_chinese4 if num < _s4: return to4(num) else: mod = _s4 high, low = num / mod, num % mod if low == 0: return to4(high) + u'万' else: if low < _s4 / 10: return to4(high) + u'万零' + to4(low) else: return to4(high) + u'万' + to4(low) def _to_chinese16(num): assert(num < _s16) to8 = _to_chinese8 mod = _s8 high, low = num / mod, num % mod if low == 0: return to8(high) + u'亿' else: if low < _s8 / 10: return to8(high) + u'亿零' + to8(low) else: return to8(high) + u'亿' + to8(low) def to_chinese(num): if type(num) != types.inttype and type(num) != types.longtype: raise notintegererror(u'%s is not a integer.' % num) if num < _min or num > _max: raise outofrangeerror(u’%d out of range[%d, %d)’ % (num, _min, _max)) if num < _s4: return _to_chinese4(num) elif num < _s8: return _to_chinese8(num) else: return _to_chinese16(num) if __name__ == '__main__': print to_chinese(9000)

把金额小写转换成大写的python代码 功能将小于十万亿元的小写金额转换为大写 代码

代码如下:

  def iif( b, s1, s2):   if b:     return s1   else:     return s2 def num2chn(nin=none):     cs = (‘零’,’壹’,’贰’,’叁’,’肆’,’伍’,’陆’,’柒’,’捌’,’玖’,’◇’,’分’,’角’,’圆’,’拾’,’佰’,’仟’, ‘万’,’拾’,’佰’,’仟’,’亿’,’拾’,’佰’,’仟’,’万’)     st = ”; st1=”     s = ‘%0.2f’ % (nin)         sln =len(s)     if sln >; 15: return none     fg = (nin

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