php与java(二)

例子1:创建和使用你自己的java类 创建你自己的java类非常容易。新建一个phptest.java文件,将它放置在你的java.class.path目录下,文件内容如下: public class phptest{ /** * a sample of a class that can work with php * nb: the whole class must be public to work, * and of course the methods you wish to call * directly. * * also note that from php the main method * will not be called */ public string foo; /** * takes a string and returns the result * or a msg saying your string was empty */ public string test(string str) { if(str.equals(“”)) { str = “your string was empty. “; } return str; } /** * whatisfoo() simply returns the value of the variable foo. */ public string whatisfoo() { return “foo is ” + foo; } /** * this is called if phptest is run from the command line with * something like * java phptest * or * java phptest hello there */ public static void main(string args[]) { phptest p = new phptest(); if(args.length == 0) { string arg = “”; system.out.println(p.test(arg)); }else{ for (int i=0; i < args.length; i++) { string arg = args[i]; system.out.println(p.test(arg)); } } } } 创建这个文件后,我们要编译好这个文件,在dos命令行使用javac phptest.java这个命令。为了使用php测试这个java类,我们创建一个phptest.php文件,内容如下: $myj = new java("phptest"); echo "test results are " . $myj->test(“hello world”) . “”; $myj->foo = “a string value”; echo “you have set foo to ” . $myj->foo . “n”; echo “my java method reports: ” . $myj->whatisfoo() . “n”; ?> 如果你得到这样的警告信息:java.lang.classnotfoundexception error ,这就意味着你的phptest.class文件不在你的java.class.path目录下。注意的是java是一种强制类型语言,而php不是,这样我们在将它们融合时,容易导致错误,于是我们在向java传递变量时,要正确指定好变量的类型。如:$myj->foo = (string) 12345678; or $myj->foo = “12345678”; 这只是一个很小的例子,你可以创建你自己的java类,并使用php很好的调用它!

http://www.bkjia.com/phpjc/629325.htmlwww.bkjia.comtruehttp://www.bkjia.com/phpjc/629325.htmltecharticle作者:井中月 例子1:创建和使用你自己的java类 创建你自己的java类非常容易。新建一个phptest.java文件,将它放置在你的java.class.path目录下,…

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